w^2-3w-10/-6w^2+24

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Solution for w^2-3w-10/-6w^2+24 equation: 


w in (-oo:+oo)

w^2-((10/(-6))*w^2)-(3*w)+24 = 0

w^2+(5/3)*w^2-3*w+24 = 0

8/3*w^2-3*w+24 = 0

DELTA = (-3)^2-(8/3*4*24)

DELTA = -247

DELTA < 0

w belongs to the empty set

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